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SAP Certified Application Associate - SAP S/4HANA R&D Engineering Sample Questions:

1. What is the advantage of the Engineering Workbench in comparison to standard material BOM and routing maintenance?Note: There are 3 correct Answers to this question.

A) Material BOMs and routings can be processed together.
B) Using a special, optional lock logic, several people can make changes to the same material BOMs and/or routings.
C) You can save changes to material BOMs and/or routings and release them for other persons without leaving the Engineering Workbench.
D) Material BOMs, routings, work centers, and material masters can be created and changed.
E) Only the Engineering Workbench allows you to make changes to material BOMs and routings using Engineering Change Management.

2. What can you do when the class status is set to locked?Note: There are 2 correct Answers to this question.

A) Find objects in this class.
B) Maintain the class.
C) Maintain a classification.
D) Assign this class to a superior class.

3. What is the significance of the control key?Note: There are 3 correct Answers to this question.

A) It is a value that can be used as a default value in the routing.
B) It defines the usage of Work Centers in routings.
C) It is an optional field in the Work Center.
D) It is a mandatory field in the Work Center.
E) It is a value that can be copied to the routing as a reference.

4. Which material types are used for configurable material masters?Note: There are 2 correct Answers to this question.

A) Each material type can be used in standard customizing for configurable material masters.
B) Material type KMAT - each material master of this material type can be configured in a fixed way.
C) Material type KMAT - configurable materials can only be created with this material type.
D) Material types KMAT, HALB, and FERT - configurable materials can only be created with these material types.

5. In a single-level configuration, you want to use a constraint so that if characteristic C1 has the value V1, then characteristic C2 is assigned the value V2.C1 and C2 are assigned to class (300)T_FCL00.What would be a correct complete constraint?

A) RESTRICTION: (300)T_FCL00.C2 = 'V2' if (300)T_FCL00.C1 = 'V1'
B) RESTRICTION: ?C2 = 'V2' if ?C1 = 'V1'
C) RESTRICTION: $self.C2 = 'V2' if $self.C1 = 'V1'
D) RESTRICTION: ?T_FCL00.C2 = 'V2' if ?T_FCL00.C1 = 'V1'

Solutions: